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參數(shù)資料
| 型號： | AD8156 |
| 廠商： | Analog Devices, Inc. |
| 英文描述： | 6.25 Gbps 4】4 Digital Crosspoint Switch with EQ |
| 中文描述： | 6.25 Gbps的4】4數(shù)字交叉點開關(guān)均衡 |
| 文件頁數(shù)： | 17/20頁 |
| 文件大小： | 376K |
| 代理商： | AD8156 |
AD8156
PROGRAMMING EXAMPLES
Rev. 0 | Page 17 of 20
A[3:0]
D[3:0]
WE
UPD
0
Figure 25. Sample Timing Diagram for 4x4 Mode Programming Examples
DUAL 2 × 2 MODE (MODE PIN = 1) PROGRAMMING EXAMPLES
Table 9. Dual 2 × 2 Mode Programming
Address Pins
A3
A2
A1
A0
1
0
0
0
1
0
0
0
1
1
0
0
1
1
0
0
Data Pins
D2
x
x
0
0
Description
A[3] = 1 enables OUT3. D[3] = 0 connects IN2 to OUT3.
A[3] = 1 enables OUT3. D[3] = 1 connects IN3 to OUT3.
A[3:2] = b11 enables OUT2 and OUT3. D[3:2] = b00 connects IN2 to both OUT2 and OUT3.
A[3:2] = b11 enables OUT2 and OUT3. D[3:2] = b10 connects IN2 to OUT2 and connects IN3
to OUT3.
A[1] = 1 enables OUT1. D[1] = 0 connects IN0 to OUT1.
D[1:0] = b11 enables OUT0 and OUT1. D[1:0] = b11 connects IN1 to both OUT0 and OUT1.
A[3:0] = b1111 enables all outputs. D[3:0] = b0101 connects IN2 to OUT3, IN3 to OUT2, IN0 to
OUT1, IN1 to OUT0.
D3
0
1
0
1
D1
x
x
x
x
D0
x
x
x
x
0
0
1
0
0
1
1
1
1
0
1
1
x
x
0
x
x
1
0
1
0
x
1
1
4 × 4 MODE (MODE PIN = 0) PROGRAMMING EXAMPLES
Table 10. Connectivity Programming, A[3:2] = b00
Address Pins
A3
A2
A1
A0
D3
0
0
0
0
0
0
0
0
0
0
0
0
1
0
0
0
0
1
1
0
Data Pins
D2
1
0
1
1
Description
A[1:0] = 0 selects OUT0. D2 = 1 enables OUT0. D[1:0] = 0 connects IN0 to OUT0.
A[1:0] = 0 selects OUT0. D2 = 0 disables OUT0. D[1:0] = 0 connects IN0 to OUT0.
A[1:0] = b10 selects OUT2. D2 = 1 enables OUT2. D[1:0] = b01 connects IN1 to OUT2.
A[1:0] = b11 selects OUT3. D2 = 1 enables OUT3. D[1:0] = b00 connects IN0 to OUT3.
D1
0
0
0
0
D0
0
0
1
0
Table 11. Output Level Programming, A[3:2] = b01
Address Pins
A3
A2
A1
A0
D3
0
1
0
0
0
0
1
0
0
1
0
1
1
0
1
0
1
1
1
0
Data Pins
D2
1
0
1
0
Description (Output Current = 2 mA + (2 mA × D[3:0])
A[1:0] = 0 selects OUT0. D[3:0] = b0100 sets OUT0 current to 2 mA + (2 mA × 4) = 10 mA.
A[1:0] = 0 selects OUT0. D[3:0] = b1000 sets OUT0 current to 2 mA + (2 mA × 8) = 18 mA.
A[1:0] = b10 selects OUT2. D[3:0] = b1101 sets OUT2 current to 2 mA + (2 mA × 13) = 28 mA.
A[1:0] = b11 selects OUT3. D[3:0] = b0000 sets OUT3 current to 2 mA + (2 mA × 0) = 2 mA.
D1
0
0
0
0
D0
0
0
1
0
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