
4-1
TM
AN9903.1
1-888-INTERSIL or 321-724-7143
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Copyright Intersil Corporation 2000
UniSLIC14 and the Texas Instruments
TCM38C17 Quad Combo
Reference Design using the UniSLIC14
and the Texas Instruments TCM38C17
Quad Combo
The purpose of this application note is to provide a reference
design for the UniSLIC14 and Texas Instruments TCM38C17
Quad Combo.
The network requirements of many countries require the
analog subscriber line circuit (SLIC) to terminate the
subscriber line with an impedance for voiceband frequencies
which is complex, rather than resistive (e.g. 600
)
. The
UniSLIC14 accomplishes this impedance matching with a
single network connected to the Z
T
pin.
The TCM38C17 Quad Combo has a programmable receive
output amplifier to adjust the output gain into the SLIC. The
output amplifier gain is programmed with two simple
resistors. Transhybrid balance is achieved via the
TCM38C17 GSX amplifier.
Discussed in this application note are the following:
2-wire 600
impedance matching.
Receive gain (4-wire to 2-wire) and transmit gain
(2-wire to 4-wire) calculations.
Transhybrid balance calculations.
Reference design for 600
2-wire load.
Reference design for China complex 2-wire load.
Impedance Matching
Impedance matching of the UniSLIC14 to the subscriber
load is important for optimization of 2 wire return loss, which
in turn cuts down on echoes in the end to end voice
communication path. It is also important for maintaining
voice signal levels on long loops. Impedance matching of the
UniSLIC14 is accomplished by making the SLIC’s impedance
(Z
SLIC
, Figure 1) equal to the desired terminating impedance
Z
0
, minus the value of the protection resistors (Z
TR
= Z
O
).
The formula to calculate the proper Z
T
for matching the
2-wire impedance is shown in Equation 1.
Equation 1 can be used to match the impedance of the SLIC
and the protection resistors (Z
TR
) to any known line
impedance (Z
O
). Figure 1 shows the calculations of Z
T
to
match a resistive and 2 complex loads.
EXAMPLE 1:
Calculate Z
T
to make Z
TR
= 600
in series with 2.16
μ
F.
R
P
= 30
.
j
ω
2.16X10
6
Z
T
= 108k
in series with 0.0108
μ
F.
Note: Some impedance models, with a series capacitor, will
cause the op-amp feedback to behave as an open circuit
DC. A resistor with a value of about 10 times the reactance
of the Z
T
capacitor (2.16
μ
F/200 = 10.8nF) at the low
frequency of interest (200Hz for example) can be placed in
parallel with the capacitor in order to solve the problem
(736k
for a 10.8nF capacitor).
EXAMPLE 2:
Calculate Z
T
to make Z
TR
= 200 + 680//0.1
μ
F
R
P
= 30
.
=
Z
T
= 28k
in series with the parallel combination of 136k
and 500pF.
Z
T
200
Z
TR
2R
P
–
(
)
=
(EQ. 1)
Z
T
200 600
–
-----------------------------------
2
( )
30
(
)
–
+
=
(EQ. 2)
Z
T
200 200
1
j
ω
680 0.1
)
X10
6
–
+
--------------------------------------------------------
2
( )
30
(
)
–
+
(EQ. 3)
FIGURE 1. IMPEDANCE MATCHING
TIP
RING
V
RX
V
TX
Z
O
V
2W
-
VS
Z
SLIC
Z
TR
V
TR
+
-
+
Z
T
Z
T
PTG
FLOATING
Z
T
RESISTIVE
R
P
30
R
P
30
Z
O
= Z
TR
= 600
Z
T
= 200(600 - 2*30)
Z
T
108k
Z
T
COMPLEX
Z
O
= Z
TR
= 200
+ 680//0.1
μ
F
Z
T
= 200(200 - 2*30)+200(680) // 0.1
μ
F/200
Z
T
28k
136k
500pF
INTERSIL
UniSLIC14
Z
T
COMPLEX
Z
O
= Z
TR
= 600
+ 2.16
μ
F
Z
T
= 200(600 - 2*30) + 2.16
μ
F/200
Z
T
108k
10.8 nF
736k
Application Note
September 2000
Authors: Don LaFontaine, Chris Ludeman