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參數資料
| 型號： | MR760RLG |
| 廠商： | ON SEMICONDUCTOR |
| 元件分類： | 參考電壓二極管 |
| 英文描述： | High Current Lead Mounted Rectifiers |
| 中文描述： | 6 A, 1000 V, SILICON, RECTIFIER DIODE |
| 封裝： | LEAD FREE, PLASTIC, CASE 194-04, 2 PIN |
| 文件頁數： | 5/7頁 |
| 文件大小： | 104K |
| 代理商： | MR760RLG |
MR750 SERIES
http://onsemi.com
5
Figure 9. Rectification Efficiency
Figure 10. Reverse Recovery Time
REPETITION FREQUENCY (kHz)
2.0
1.0
100
50
30
20
70
3.0
5.0
100
R
70
7.0 10
20
30
50
T
J
= 25
°
C
CURRENT INPUT WAVEFORM
I
R
/I
F
, RATIO OF REVERSE TO FORWARD CURRENT
0.2
0.1
20
7.0
5.0
2.0
1.0
7.0
0.3
0.5
10
3.0
tr
10
0.7 1.0
2.0
3.0
5.0
T
J
= 25
°
C
I
F
= 5 A
3 A
1 A
I
F
0
I
R
t
rr
Figure 11. Junction Capacitance
Figure 12. Forward Recovery Time
V
R
, REVERSE VOLTAGE (VOLTS)
1.0
3.0
500
300
200
100
70
50
2.0
C
10
20
100
7.0
5.0
50
30
T
J
= 25
°
C
1.0
I
F
, FORWARD PULSE CURRENT (AMP)
0.7
0.5
0.3
0.2
0.1
2.0
,
tf
5.0
3.0
1.0
7.0
10
fr
= 1.0 V
T
J
= 25
°
C
fr
f
t
fr
T
J
= 175
°
C
30
700
1000
30
20
10
70
fr
= 2.0 V
R
S
R
L
V
O
Figure 13. SinglePhase HalfWave
Rectifier Circuit
The rectification efficiency factor
σ
shown in Figure 9
was calculated using the formula:
σ
P
(dc)
P
(rms)
V
2
o
(dc)
R
L
V
2
o
(rms)
R
L
.100%
V
2
o
(dc)
V
2
o
(
ac)
V
2
o
(dc)
.100%
(1)
For a sine wave input V
m
sin (wt) to the diode, assumed
lossless, the maximum theoretical efficiency factor becomes:
σ
(sine)
V
2m
2
R
L
V
2m
4R
L
.100%
4
π
2
.100%
40.6%
(2)
For a square wave input of amplitude V
m
, the efficiency
factor becomes:
σ
(square)
V
2m
2
R
L
V
2m
R
L
.100%
50%
(3)
(A full wave circuit has twice these efficiencies)
As the frequency of the input signal is increased, the
reverse recovery time of the diode (Figure 10) becomes
significant, resulting in an increasing AC voltage
component across R
L
which is opposite in polarity to the
forward current, thereby reducing the value of the efficiency
factor
σ
, as shown on Figure 9.
It should be emphasized that Figure 9 shows waveform
efficiency only; it does not provide a measure of diode
losses. Data was obtained by measuring the AC component
of V
o
with a true rms AC voltmeter and the DC component
with a DC voltmeter. The data was used in Equation 1 to
obtain points for Figure 9.
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