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參數(shù)資料
型號: TPA6021A4NE4
廠商: TEXAS INSTRUMENTS INC
元件分類: 音頻控制
英文描述: 2 CHANNEL(S), VOLUME CONTROL CIRCUIT, PDIP20
封裝: ROHS COMPLIANT, PLASTIC, MS001-AD, DIP-20
文件頁數(shù): 13/25頁
文件大小: 1823K
代理商: TPA6021A4NE4
www.ti.com
V(LRMS)
VO
IDD
IDD(avg)
Efficiency of a BTL amplifier +
P
L
P
SUP
Where:
P
L +
V
Lrms
2
R
L
, and V
LRMS +
V
P
2
, therefore, P
L +
V
P
2
2R
L
and PSUP + VDD IDDavg
and
I
DDavg +
1
p
0
V
P
R
L
sin(t) dt
+
1
p
V
P
R
L
[cos(t)]
p
0 +
2V
P
p
R
L
Therefore,
P
SUP +
2 V
DD VP
p
R
L
(7)
Efficiency of a BTL amplifier +
V
P
2
2 R
L
2 V
DD VP
p
R
L
+
p
V
P
4 V
DD
PL = Power delivered to load
PSUP = Power drawn from power supply
VLRMS = RMS voltage on BTL load
RL = Load resistance
V
P +
2 P
L RL
hBTL +
p
2 P
L RL
4 V
DD
Where:
Therefore,
VP = Peak voltage on BTL load
IDDavg = Average current drawn from the power supply
VDD = Power supply voltage
ηBTL = Efficiency of a BTL amplifier
(8)
TPA6021A4
SLOS465 – JUNE 2005
Figure 28. Voltage and Current Waveforms for BTL Amplifiers
Although the voltages and currents for SE and BTL are sinusoidal in the load, currents from the supply are very
different between SE and BTL configurations. In an SE application the current waveform is a half-wave rectified
shape, whereas in BTL it is a full-wave rectified waveform. This means RMS conversion factors are different.
Keep in mind that for most of the waveform both the push and pull transistors are not on at the same time, which
supports the fact that each amplifier in the BTL device only draws current from the supply for half the waveform.
The following equations are the basis for calculating amplifier efficiency.
substituting PL and PSUP into Equation 7,
Table 3 employs Equation 8 to calculate efficiencies for four different output power levels. Note that the efficiency
of the amplifier is quite low for lower power levels and rises sharply as power to the load is increased resulting in
a nearly flat internal power dissipation over the normal operating range. Note that the internal dissipation at full
output power is less than in the half power range. Calculating the efficiency for a specific system is the key to
proper power supply design. For a stereo 1-W audio system with 8-
loads and a 5-V supply, we get an
efficiency of 0.628. Total output power is 2-W. Thus the maximum draw on the power supply is almost 3.25 W.
20
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