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參數(shù)資料
| 型號(hào)： | TS4973EIJT |
| 廠商： | STMICROELECTRONICS |
| 元件分類(lèi)： | 音頻／視頻放大 |
| 英文描述： | 1.2 W, 1 CHANNEL, AUDIO AMPLIFIER, BGA9 |
| 封裝： | LEAD FREE, FCP-9 |
| 文件頁(yè)數(shù)： | 6/19頁(yè) |
| 文件大小： | 721K |
| 代理商： | TS4973EIJT |
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TS4973
Application Information
14/19
3
Application Information
3.1 BTL Configuration Principle
The TS4973 are monolithic power amplifiers with
a BTL output type. BTL (Bridge Tied Load) means
that each end of the load is connected to two
single-ended output amplifiers. Thus, we have:
Single ended output 1 = Vout1 = Vout (V)
Single ended output 2 = Vout2 = -Vout (V)
And Vout1 - Vout2 = 2Vout (V)
The output power is:
For the same power supply voltage, the output
power in BTL configuration is four times higher
than
the
output
power
in
single
ended
configuration.
3.2 Gain In Typical Application Schematic
(cf. page1 of TS4973 datasheet)
Depending on gain select (Gs) voltage, the output
is driven by In1 when Gs
≥1.5V and by In2 when
Gs
≤0.4V. In the flat region (no C
IN effect), the gain
is expressed by this general equation:
If Gs
≤ 0.4V: The typical value is
with a range of:
If Gs
≥ 1.5V: The typical value is (Rin in k)
with a range of :
Remark: Vout2 is in phase with Vin and Vout1 is
phased 180
° with Vin. This means that the
positive terminal of the loudspeaker should be
connected to Vout2 and the negative to Vout1.
3.3 Low frequency response
In the low frequency region, CIN starts to have an
effect. CIN forms with RIN (or the input impedance
Zin when Gs
≤ 0.4V) a high-pass filter with a -3dB
cut off frequency.
If Gs
≤ 0.4V: The typical value is (Cin
2 in nF)
with a range of
If Gs
≥ 1.5V: The value is (Rin in k, Cin
1 in nF):
3.4 Power dissipation and efficiency
Hypothesis:
l Load voltage and current are sinusoidal (Vout
and Iout)
l Supply voltage is a pure DC source (Vcc)
Regarding the load we have:
and
Then, the average current delivered by the supply
voltage is:
The power delivered by the supply voltage is:
Psupply = Vcc IccAVG (W)
Then, the power dissipated by the amplifier is:
Pdiss = Psupply - Pout (W)
and the maximum value is obtained when:
and its value is:
)
W
(
R
)
Vout
2
(
Pout
L
2
RMS
=
)
2
,
1
(
2
1
Vin
Vout
Av
=
2
Vin
Vout
Av
2
1
=
=
1
.
2
Vin
Vout
Av
9
.
1
2
1
≤
=
≤
Rin
100
Vin
Vout
Av
1
2
1
=
=
Rin
125
Vin
Vout
Av
Rin
75
1
2
1
≤
=
≤
)
Hz
(
C
4823
F
2
in
CL =
2
in
CL
2
in
C
3789
)
Hz
(
F
C
6366
≤
)
Hz
(
C
Rin
159000
F
1
in
CL ≤
)
V
(
t
sin
V
PEAK
OUT
ω
=
)
A
(
R
V
I
L
OUT
OUT =
)
W
(
R
2
V
P
L
2
PEAK
OUT =
)
A
(
R
V
2
Icc
L
PEAK
AVG
π
=
)
W
(
P
R
Vcc
2
Pdiss
OUT
L
π
=
0
P
Pdiss
OUT
=
)
W
(
R
Vcc
2
max
Pdiss
L
2
π
=
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|---|---|
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