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參數資料
| 型號： | ADP1610 |
| 廠商： | Analog Devices, Inc. |
| 英文描述： | 1.2 MHz DC-DC Step-Up Switching Converter |
| 中文描述： | 1.2兆赫的DC - DC升壓轉換器 |
| 文件頁數： | 12/16頁 |
| 文件大小： | 948K |
| 代理商： | ADP1610 |
ADP1610
DIODE SELECTION
The output rectifier conducts the inductor current to the output
capacitor and load while the switch is off. For high efficiency,
minimize the forward voltage drop of the diode. For this reason,
Schottky rectifiers are recommended. However, for high voltage,
high temperature applications, where the Schottky rectifier
reverse leakage current becomes significant and can degrade
efficiency, use an ultrafast junction diode.
Rev. 0 | Page 12 of 16
Make sure that the diode is rated to handle the average output
load current. Many diode manufacturers derate the current
capability of the diode as a function of the duty cycle. Verify
that the output diode is rated to handle the average output load
current with the minimum duty cycle. The minimum duty cycle
of the ADP1610 is
OUT
V
MAX
IN
OUT
V
MIN
V
D
=
(12)
where
V
IN-MAX
is the maximum input voltage.
Table 6. Schottky Diode Manufacturers
Vendor
Phone No.
Motorola
602-244-3576
Diodes, Inc.
805-446-4800
Sanyo
310-322-3331
Web Address
www.diodes.comwww.irf.com
LOOP COMPENSATION
The ADP1610 uses external components to compensate the
regulator loop, allowing optimization of the loop dynamics for a
given application.
The step-up converter produces an undesirable right-half plane
zero in the regulation feedback loop. This requires compensat-
ing the regulator such that the crossover frequency occurs well
below the frequency of the right-half plane zero. The right-half
plane zero is determined by the following equation:
L
R
2
V
V
RHP
F
LOAD
×
π
OUT
IN
Z
×
=
)
(
2
(13)
where:
F
Z
(RHP)
is the right-half plane zero.
R
LOAD
is the equivalent load resistance or the output voltage
divided by the load current.
To stabilize the regulator, make sure that the regulator crossover
frequency is less than or equal to one-fifth of the right-half
plane zero and less than or equal to one-fifteenth of the
switching frequency.
The regulator loop gain is
OUT
CS
COMP
MEA
OUT
IN
OUT
FB
VL
Z
G
Z
G
V
V
V
V
A
×
×
×
×
×
=
(14)
where:
A
VL
is the loop gain.
V
FB
is the feedback regulation voltage, 1.230 V.
V
OUT
is the regulated output voltage.
V
IN
is the input voltage.
G
MEA
is the error amplifier transconductance gain.
Z
COMP
is the impedance of the series RC network from COMP to
GND.
G
CS
is the current sense transconductance gain (the inductor
current divided by the voltage at COMP), which is internally set
by the ADP1610.
Z
OUT
is the impedance of the load and output capacitor.
To determine the crossover frequency, it is important to note
that, at that frequency, the compensation impedance (Z
COMP
) is
dominated by the resistor, and the output impedance (Z
OUT
) is
dominated by the impedance of the output capacitor. So, when
solving for the crossover frequency, the equation (by definition
of the crossover frequency) is simplified to
1
2
1
|
|
=
×
×
×
×
×
×
×
=
OUT
C
C
CS
COMP
R
MEA
OUT
V
IN
OUT
V
FB
VL
f
G
G
V
V
A
π
(15)
where:
f
C
is the crossover frequency.
R
COMP
is the compensation resistor.
Solving for R
COMP
,
CS
MEA
IN
FB
OUT
OUT
OUT
×
C
COMP
G
G
V
V
V
V
C
f
R
×
×
×
×
×
×
=
π
2
(16)
For
V
FB
= 1.23,
G
MEA
= 100 μS, and
G
CS
= 2 S,
IN
OUT
V
OUT
V
OUT
V
C
COMP
C
f
R
×
×
×
×
×
=
4
10
55
.
(17)
Once the compensation resistor is known, set the zero formed
by the compensation capacitor and resistor to one-fourth of the
crossover frequency, or
COMP
C
COMP
R
f
C
×
×
π
=
2
(18)
where
C
COMP
is the compensation capacitor.
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